资料: AB=2
BC=10
ABCD=20
EFD= ABF+10--------------------------------->(1)
做法:
ABF=(1/2)(AB)(AF)
ABF=(1/2)(2)(AF)
ABF=AF
AFB = ABCD-FDCB
(1/2)(AB)(AF) = 20 - (1/2)(FD+BC)(DC)
(1/2)(2)(AF) = 20 - (1/2)(FD+10)(2)
AF = 20-(FD+10)
AF=10-FD
BEC = EFD +FDBC
BEC = EFD + (1/2)(FD+10)(2)
BEC = EFD +FD +10 ----------------------------------->(2)
Sub (1) into (2)
BEC= ABF +10+FD+10
BEC = ABF +20+FD--------------------------------------->(3)
Since ABF =AF and AF =10-FD ,hence from (3)
BEC = AF+20+FD
BEC= (10-FD)+20+FD)
BEC = 30
BEC= (1/2)(BC)(ED+DC)
30 = (1/2)(10)(ED+2)
30 =(5)(ED+2)
ED=4