2t(m-1)=t-1
m-1=t-1/2t
m=(t-1/2t)+1
m=(t-1+2t)/2t
m=3t-1/2t
=[2n(m+2)/(3-n)(3+n)]x3-n/6mn
=m+2/(3+n)(3m)
[(y-6)/3-(y-4)/2=1]x6
2y-12-3y+12=6
-y=6
y=-6
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【数学问题】求算法!十六题 (完成度:16/16)>>>完毕<<< |
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