jessamoment 发表于 2013-1-14 05:39 PM
SELECT 名字, 薪水, @curRow := @curRow + 1 AS 排名
FROM table
JOIN (SELECT @curRow := 0) r
兴杰 发表于 2013-1-21 01:20 AM
set @a=0;
select concat('第',(@a:=@a+1),'名') as ranking ,name,salary from table1 order by salary d ...
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